How can I add a value of a list to its own sublist? Input list:

list = ['apple', 'tesla', 'amazon']

My approach so far:

While True:
 
    list = []

    for comp in list:

            #do some modification

            list.append(comp)

Desired printed output is:

'apple', 'apple','apple', etc.
'tesla', 'tesla','tesla', etc.
'amazon','amazon','amazon', etc.

CodePudding user response：

If you change your orignal list to a list of lists it can be done as:

list = [['apple'], ['tesla'], ['amazon']]

while True:
    for i in range(len(list)):
        list[i].append(list[i][0])

The output on each iteration would be something like:

# for iteration 1
['apple', 'apple']
['tesla', 'tesla']
['amazon', 'amazon']

# for iteration 2
['apple', 'apple', 'apple']
['tesla', 'tesla', 'tesla']
['amazon', 'amazon', 'amazon']

CodePudding user response：

list = ['apple', 'tesla', 'amazon']
for idx, item in enumerate(list):
    text = (list[idx] ",")*len(list)
    print(text[:-1])

apple,apple,apple
tesla,tesla,tesla
amazon,amazon,amazon

CodePudding user response：

I can think of a couple of ways - I am using the length of each item in the list to define a condition here as you did not specify the condition you are using to move on to the next item -

Option 1 - using a for with a while loop

l = ['apple', 'tesla', 'amazon'] 
x = 0
for comp in l:
    while x < len(comp):
        print(comp)
        x  = 1
    x = 0

Option 2 - using while with a iter

l = ['apple', 'tesla', 'amazon'] 
x = 0
it = iter(l)
while True:
    try:   
        item = next(it)
        while x < len(item):
            print(item)
            x  = 1
        x = 0
    except StopIteration:
        break

In both cases - the output is

apple
apple
apple
apple
apple
tesla
tesla
tesla
tesla
tesla
amazon
amazon
amazon
amazon
amazon
amazon