Click all buttons and skip one when I get error exception,then continue clicking all of them. After-CodePudding

This

P.S: I would like to point out that my question is for personal and informational study purposes only. I am new to Python and am now learning Selenium. I don't want to use spam and don't really want to use the script in real cases. Respect for Facebook rules. As I said, my question is just a curiosity for reasons of personal study to understand the code of this curiosity of mine.

CodePudding user response：

You are trying to send a given number of requests and skip bad requests in a overly complicated way. This is likely the simplest way to do it:

check if an user has the “Add Friend” button

if yes, click the button

if the error box appears, close it, otherwise increment by 1 the number of sent requests

if the desired number of requests were sent, stop, otherwise go to the next user

.

requests_to_send = 20 requests_sent = 0 requests_failed = 0 i = 0 # number of users checked users = [] while requests_sent < requests_to_send: # if necessary, wait until new users are loaded while i >= len(users): users = driver.find_elements(By.CSS_SELECTOR, 'div[aria-label=Reactions] div:nth-child(3) div[data-visualcompletion=ignore-dynamic]') time.sleep(.5) driver.execute_script('arguments[0].scrollIntoView({block: "center"});', users[i]) button = users[i].find_elements(By.CSS_SELECTOR, 'div[aria-label="Add Friend"]') if button: button[0].click() time.sleep(2) cant_send = driver.find_elements(By.CSS_SELECTOR, 'div[aria-label=OK]') if cant_send: requests_failed = 1 cant_send[0].click() # wait until popup is closed while driver.find_elements(By.CSS_SELECTOR, 'div[aria-label=OK]'): time.sleep(.5) else: requests_sent = 1 i = 1 print(f'users checked {i} - req. sent {requests_sent} - req. failed {requests_failed}', end='\r')

p.s. fanne buono uso!