C Is it possible to overload a function so that its argument accept literal and reference respecti-CodePudding

I'm having a problem with using C overloading and was wondering if anybody could help.

I'm trying to overload functions so that its argument accept reference and literal respectively.

For example, I want to overload func1 and func2 to func:

int func1 (int literal); 
int func2 (int &reference);

and I want to use func in this situations:

func(3);   // call func1
int val = 3;
func(val); // I want func2 to be called, but ambiguous error

Is there any way to overload these functions?

thanks! Any help would be appreciated! sorry for poor english.

CodePudding user response：

#include <iostream>

void foo1(int &) { std::cout << "int &\n"; }
void foo1(const int &) { std::cout << "const int &\n"; }

void foo2(int &) { std::cout << "int &\n"; }
void foo2(const int &) { std::cout << "const int &\n"; }
void foo2(int &&) { std::cout << "int &&\n"; }
void foo2(const int &&) { std::cout << "const int &&\n"; }

int bla() { return 1; }

int main() {
    int x{}, y{};
    std::cout << "foo1:\n";
    foo1(1);
    foo1(x);
    foo1(std::move(x));
    foo1(bla());
    std::cout << "\nfoo2:\n";
    foo2(1);
    foo2(y);
    foo2(std::move(y));
    foo2(bla());
}

Output:

foo1:
const int &
int &
const int &
const int &

foo2:
int &&
int &
int &&
int &&