String[] ergebnisse = {"Err", "Baum", "Schule", "Pferd", "Maschine"};
String eingabe = textField1.getText();
int[] punkte = new int[ergebnisse.length];

for (int w = 0; w < ergebnisse.length; w  ) {
      for (int b = 0; b < ergebnisse[w].length(); b  ) {
        if (ergebnisse[w].charAt(b) == eingabe.charAt(b)) {
          punkte[w]  ;   
        }
      }
    }

Error Oud of Bounds only apears in the if case on the second run. if i replace if(ergebnisse[w].charAt(b)) == eingabe.charAt(X)) it works but only for thr one caracter.

CodePudding user response：

Let's say you input "Pferd".

Your code runs once for each ergebnisse, so eventually it gets to Schule.

schule's length is 6, of course. So that for (int b ) loop is going to run 6 times. Unfortunately, you're going to run into real issues on that 6th run (where b is 5): eingabe.charAt(5) - that does not work - there is no 6th character in eingabe, as eingabe has only 5 letters in it.

The fix is to deal with that. You can't switch it up and change the loop to for (int b = 0; b < eingabe.length(); b ) either - what if the eingabe is longer than one of the ergebnisse?

You could go by whichever one is smaller:

for (int b = 0; i < Math.min(eingabe.length(), ergebnisse[w].length()); b  )`

You could also simply 'detect' this is pick some action:

if (b < eingabe.length() && ergebnisse[w].charAt(b) == eingabe.charAt(b)) {

for example.

You need to pick one of the two to 'scan length'