Given a sorted list of integers, square the elements and give the output in sorted order-CodePudding

Can anybody help me with this. I don't know what am I doing wrong over here

list = [-9, -2, 0, 2, 3]
squared_list=[]


for element in list:
    squaring = list[element] * list[element]
    squared_list.append(squaring)

squared_list.sort()
print(squared_list)

CodePudding user response：

Use squaring = element * element against squaring = list[element] * list[element] because for the first element, for example, you're consulting list[-9] and that index is out.

CodePudding user response：

Solution

list = [-9, -2, 0, 2, 3]
squared_list=[]


for element in list:
    squaring = element**2
    squared_list.append(squaring)

squared_list.sort()
print(squared_list)

OR shorter version :)

list = [-9, -2, 0, 2, 3]
squared_list=[element**2 for element in list]