I am trying to find the number of 3 digit numbers that has 2 numbers that are the factors of the third. So for example, 248 would be valid since 2 * 4 = 8 and 933 would also be valid since 3 * 3 = 9.
using System;
class Program
{
public static void Main (string[] args)
{
int Total = 0;
for (int i = 100; i < 1000; i )
{
string I = Convert.ToString(i);
Console.WriteLine(I[2] " " I[1] " " I[0] " " I);
if (I[2] == I[1] * I[0] || I[1] == I[0] * I[2] || I[0] == I[2] * I[1])
{
Console.WriteLine("true");
Total ;
}
}
Console.WriteLine("the total is");
Console.WriteLine(Total);
}
}
CodePudding user response:
When you access a string by index, you get a char
and not an int. To get an int out of a char, you have to parse it back:
var a = int.Parse(I[0].ToString());
var b = int.Parse(I[1].ToString());
var c = int.Parse(I[2].ToString());
Then you can do your multiplication like a == b * c
and so on