Do you know if it was possible to return 2 values in 2 columns with one def?
I have this two def:
def codeAcro (row):
NOVA, Concordance = row['Code'], row['Concordance']
if pd.isna(Concordance) == True:
return None
else:
return Concordance
ListeCodeNova['Acronyme'] = ListeCodeNova[['Concordance','Code']].apply(codeAcro, axis=1)
def codeNOVA (row):
NOVA, Concordance = row['Code'], row['Concordance']
if pd.isna(Concordance) == True:
return None
else:
return NOVA
ListeCodeNova['Concordance'] = ListeCodeNova[['Concordance','Code']].apply(codeNOVA, axis=1)
And i want to know if it was possible to simplify in just one def.
CodePudding user response:
For performance more better to avoid the apply method (which is called for every row), and use boolean indexing instead:
import pandas as pd
import numpy as np
df = pd.DataFrame({'Concordance':[1, np.nan, 2], 'Code':[10, 11,12]})
mask = df.Concordance.notna()
df['Acronyme'] = np.where(mask, df.Concordance, None)
df['Concordance'] = np.where(mask, df.Code, None)