Iterating over dictionaries to check for duplicates-CodePudding

I am trying to find matching names in a dictionary. The user sends a request that looks like this:

req= [{"host":"usr1"}, {"host":"usr7"}, {"host":"usr10"}, {"host":"usr11"}, {"host":"usrx...."}, ..../more hosts]

Then I check for matches in another dictionary that looks like this:

data = [
        {
            "host": "usr1",
            "address": "x"
        },
        {
            "host": "usr2",
            "address": "y"
        },
        {
            "host": "usr3",
            "address": "z"
        }
          .../ more hosts
    ]

if there is a match between the request from the user and the database I want to pop that host. I tried like this:

new_static = []
for x, i in zip(data, req):    
    if i['host'] != x['host']:
            new_static.append(x)
    data = new_static
    continue

it works, but here a problem occurs if len of the req and the data is not equal, I also tried with double nested loops but with no success. Any help will be helpful

CodePudding user response：

You can try with the following nested loop solution:

req= [{"host":"usr1"}, {"host":"usr7"}, {"host":"usr10"}, {"host":"usr11"}]
data = [
        {
            "host": "usr1",
            "address": "x"
        },
        {
            "host": "usr2",
            "address": "y"
        },
        {
            "host": "usr3",
            "address": "z"
        }]
    
for i in req:    
    for j in data:
        if i["host"] == j["host"]:
            print("Host: ", i["host"])

Output:

Host:  usr1

CodePudding user response：

Assuming the objects in your request only contain one key, you can simplify it to a set for efficiency. Then, assuming you want to filter the elements of data that have a host not in req, this can be accomplished by:

hosts_request = set(el['host'] for el in req)
filtered_data = [entry for entry in data if entry['host'] not in hosts_request]

CodePudding user response：

sinmple = [e["host"] for e in data]
for r in req:
    if r["host"] in simple:
        pass
        # do something with the duplicat