Exposing Resources using Tomcat Server-CodePudding

After debugging for a few hours, I am seeking help to set up a REST API using Jersey in Java. I am using a Tomcat 6 server and the following is my file structure of the Mavin project:

On the right, the resource which I want to expose can be seen.

For the web.xml I have a file as follows:

<?xml version="1.0" encoding="UTF-8"?>
<!-- This web.xml file is not required when using Servlet 3.0 container,
 see implementation details https://github.com/jax-rs -->
<web-app version="2.5">
  <servlet>
    <servlet-name>Jersey Web Application</servlet-name>
    <servlet-class>org.glassfish.jersey.servlet.ServletContainer</servlet-class>
    <init-param>
      <param-name>jersey.config.server.provider.packages</param-name>
      <param-value>com.howtodoinjava.demo</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
  </servlet>
  <servlet-mapping>
    <servlet-name>Jersey Web Application</servlet-name>
    <url-pattern>/webapi/*</url-pattern>
  </servlet-mapping>
</web-app>

and for the pom.xml as follows:

<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/maven-v4_0_0.xsd">

<modelVersion>4.0.0</modelVersion>

<groupId>com.howtodoinjava.demo</groupId>
<artifactId>JerseyArcheTypeDemo</artifactId>
<packaging>war</packaging>
<version>0.0.1-SNAPSHOT</version>
<name>JerseyDemo</name>

<build>
    <finalName>JerseyArcheTypeDemo</finalName>
    <plugins>
        <plugin>
            <groupId>org.apache.maven.plugins</groupId>
            <artifactId>maven-compiler-plugin</artifactId>
            <version>2.5.1</version>
            <inherited>true</inherited>
            <configuration>
                <source>1.7</source>
                <target>1.7</target>
            </configuration>
        </plugin>
    </plugins>
</build>

<dependencyManagement>
    <dependencies>
        <dependency>
            <groupId>org.glassfish.jersey</groupId>
            <artifactId>jersey-bom</artifactId>
            <version>${jersey.version}</version>
            <type>pom</type>
            <scope>import</scope>
        </dependency>
    </dependencies>
</dependencyManagement>

<dependencies>
    <dependency>
        <groupId>org.glassfish.jersey.containers</groupId>
        <artifactId>jersey-container-servlet-core</artifactId>
        <!-- use the following artifactId if you don't need servlet 2.x compatibility -->
        <!-- artifactId>jersey-container-servlet</artifactId -->
    </dependency>
    <!-- uncomment this to get JSON support
    <dependency>
        <groupId>org.glassfish.jersey.media</groupId>
        <artifactId>jersey-media-moxy</artifactId>
    </dependency>
    -->
</dependencies>
<properties>
    <jersey.version>2.20</jersey.version>
    <project.build.sourceEncoding>UTF-8</project.build.sourceEncoding>
</properties>

I can build the Maven project and start the server. However if I want to add resources to the Server by right-clicking on the server name and clicking on "Add or Remove..." I get a message that I cannot select any resources. I followed the adivce in this question:

CodePudding user response：

You can't select this project because Tomcat 6 does not support Servlet 4.0 projects. Servlet 4.0 requires Tomcat 9.x, which itself requires Java 1.8. See the Tomcat documentation.

You can lower the facet version, but it makes far more sense to simply use the newer Tomcat version. Tomcat 6 is far past its end-of-life.