I have a date/time column saved like this 20200821144500. How do I convert it to date and time format? I tried as.POSIXct('20200821144500',format="%Y-%m-%d %H:%M:%S") which returned NA. Am I using the wrong format or is there another way to do it?
CodePudding user response:
A possible solution, based on lubridate::ymd_hms
:
lubridate::ymd_hms("20200821144500")
#> [1] "2020-08-21 14:45:00 UTC"
CodePudding user response:
The main feature here is to tell which is first year month or day etc.. in the string. and to use HMS , because:
- hms, hm and ms usage is defunct, please use HMS, HM or MS instead. Deprecated in version '1.5.6'.
library(lubridate)
string <- "20200821144500"
parse_date_time(string, "ymd_HMS")
[1] "2020-08-21 14:45:00 UTC"
CodePudding user response:
Another option using strptime
with right format
:
strptime(as.character(20200821144500),format="%Y%m%d%H%M%S")
#> [1] "2020-08-21 14:45:00 CEST"
Created on 2022-07-08 by the reprex package (v2.0.1)