Remove an item from object based on existence in second object-CodePudding

I have the following 2 objects. How can I remove items from listProposalProducts that don't have a coverageLineId that matches an id from coverageLinesSelectedItems? In this example, I want to remove item 1 from listProposalProducts because an id of 2 does not exist in coverageLinesSelectedItems. I think I'm looking for the opposite of the pop() method but I'm not sure how to get the correct index to splice out of listProposalProducts.

let listProposalProducts = [
    0: {productId: 101391, coverageLineId: 1}, 
    1: {productId: 101591, coverageLineId: 2},
    2: {productId: 151391, coverageLineId: 3}
]

let coverageLinesSelectedItems =  [
    0: {id: 1, itemName: 'Medical'},
    3: {id: 3, itemName: 'Vision'}
]

CodePudding user response：

You could use Array.filter combined with Array.some to filter the results. E.g.

let listProposalProducts = [
    0: {productId: 101391, coverageLineId: 1}, 
    1: {productId: 101591, coverageLineId: 2},
    2: {productId: 151391, coverageLineId: 3}
]

let coverageLinesSelectedItems =  [
    0: {id: 1, itemName: 'Medical'},
    3: {id: 3, itemName: 'Vision'}
]

let requiredResult = listProposalProducts.filter(
  item => coverageLinesSelectedItems.some(
    cov => cov.id === item.coverageLineId
  )
);

This keeps only the products whose coverageLineId matches the id of a coverageLinesSelectedItems element.

CodePudding user response：

A simple straight forward implementation would be:

listProposalProducts.filter((it) => coverageLinesSelectedItems.find((other) => other.id === it.coverageLineId))

If the objects are larger, you might want to compute a map from the lookup object.

const lookup = {}
coverageLinesSelectedItems.forEach((it) => {lookup[it.id] = true;})
listProposalProducts.filter((it) => lookup[it.coverageLineId])