bash loop adds single quotes-CodePudding

maybe someone here can enlighten me:

function:

add_repo() {
  for repo in "${repos[@]}"; do
    sudo flatpak remote-add --if-not-exists "$repo"
  done
}

script:

#! /usr/bin/env bash

repos=(
  "flathub https://flathub.org/repo/flathub.flatpakrepo"
)

source function

add_repo

output:

sudo flatpak remote-add --if-not-exists 'flathub https://flathub.org/repo/flathub.flatpakrepo'

output without quotation on $repo:


sudo flatpak remote-add --if-not-exists flathub https://flathub.org/repo/flathub.flatpakrepo

This is the desired output.

Question: How can I quote the variable without added single quotes? I know, that set -x (set only for debugging) adds these single quotes to allow for better reading, but somehow the command ends after --if-not-exists because of the added single quotes even without set -x.

CodePudding user response：

When consuming subset groups of values from a list; it is convenient to have a function or a command to pop-out needed values from list's values passed as arguments.

Here, create the addrepos bash script command, so it can be invoked with sudo, elevating privileges only once to add all repositories.

#!/usr/bin/env bash
# addrepos NAME URL [ NAME URL ] ...

# While there are arguments
while [ "$#" -gt 0 ]; do
  # Pops repository name from arguments
  repo_name="${1}"
  shift
  # Pops repository URL from arguments
  repo_url="${1}"
  shift

  flatpak remote-add --if-not-exists "${repo_name}" "${repo_url}"
done

Make it executable:

chmod  x addrepos

The main script call the addrepo script with sudo:

#! /usr/bin/env bash

# repository name and url are distinct entries in the repos array
repos=(
  'flathub' 'https://flathub.org/repo/flathub.flatpakrepo'
)

# sudo call addrepos with the content of the repos array as arguments
sudo ./addrepos "${repos[@]}"