For example, I want to download the pictures to the folder named pictures. How can I do this with urllib request
import os
import urllib.request
try:
klasor_yarat = os.mkdir("resimler")
except:
pass
say = 1
for i in resim_listesi:
urllib.request.urlretrieve(i,str(klasor_yarat) "\"resim" str(say) ".jpg")
say =1
CodePudding user response:
os.mkdir()
doesn't return anything, so klasor_yarat
doesn't have any value in your code. Instead, create the path like this:
import os
import urllib.request
resimler = "resimler"
try:
os.mkdir(resimler)
except:
pass
say = 1
for i in resim_listesi:
urllib.request.urlretrieve(i, os.path.join(resimler, "resim" str(say) ".jpg"))
say =1
Use os.path.join()
to create paths in a platform-independent way, instead of trying to add slashes yourself.
CodePudding user response:
This should be achievable through specifying the directory inside of your file name/path for the image.
For example:
import os
import urllib
try:
os.mkdir("directory")
except:
pass
url = "https://www.google.com/images/branding/googlelogo/1x/googlelogo_light_color_272x92dp.png"
urllib.request.urlretrieve(URL, "directory/google.png")
CodePudding user response:
There seem to be several problems here:
"\"resim"
is not the correct way to put a'/'
in the string. You have to use"/"
or"\\"
.str(klasor_yarat)
returns"None"
.- You are adding a
".jpg"
to the image retrieved. What if the image is a different extension? - Make sure
resim_listesi
is an iterable. I can't know that because it's not defined in the code given. - Lastly, try using English names for variables as that will improve the readability of your code for others.
Anyway, this should probably work.
import os
import urllib.request
try:
klasor_yarat = os.mkdir("resimler")
except:
pass
say = 1
for i in resim_listesi:
urllib.request.urlretrieve(i,"resimler/resim" str(say) ".jpg")
say =1