"Table1":
id | name |
---|---|
1 | Ulrich |
2 | Stern |
"Table2":
id | school | tid |
---|---|---|
1 | A | 1 |
2 | B | 1 |
I want to join 2 table to get all information. With SQL query like this:
SELECT Table1.id,
name,
school
FROM `Table1`
INNER JOIN `Table2`
ON Table1.id = Table2.tid
It gives me all information as I expect (I mean 2 rows with name 'Ulrich').
But when I do with Yii2 query:
$query = self::find();
$query -> alias('t1')
-> innerJoin(['t2'=>'Table2'], 't1.id=t2.tid')
$result = NULL;
if($total = $query->count()) {
$result = $query
-> select([t1.*, t2.school])
->asArray()
->all()
;
$result[0]['count'] = $total;
}
it only gives me 1 row with name 'Ulirch'.
Can anyone help me with this problem. Thank you very much.
CodePudding user response:
If you use ActiveRecord::find()
method to create query you will get instance of yii\db\ActiveQuery
. This is query designed to load ActiveRecord
models. Because of that if you do any type of join and your result set contains primary key of your main model (The model which find()
method was called to create query) the ActiveQuery
will remove any rows it considers duplicate.
The duplicates are recognised based on main model primary key so the rows in resultset will be considered duplicate even if the data from joined table are different. That's exactly what happened in your case.
To avoid that you have to use query builder instead of ActiveQuery
.
Your query can look for example like this:
$query = (new \yii\db\Query())
->from(['t1' => self::tableName()])
->innerJoin(['t2'=>'Table2'], 't1.id=t2.tid');