sorting a list of females and males-CodePudding

I have an input:

4
m.hosSein.python
f.miNa.C
m.aHMad.C  
f.Sara.java

and I must sort it in the way that first comes all f(females) ordered by alphabet then comes all m(males) ordered by alphabet. This is the desirable output:

f Mina C
f Sara java
m Ahmad C  
m Hossein python

.here is my code:

`n=int(input())
lst=[]
for i in range (0,n):
x=input().split('.')
lst.append(x)
list=sorted(lst,key=lambda x:(x[0],x[1]))

for item in lst:
if item[0]=='f':
    print(item[0],item[1].capitalize(),item[2])
else:
    print(item[0],item[1].capitalize(),item[2])`

my code dose not sort f.(females) correctly and Sara comes first. Could anybody help me?

CodePudding user response：

Try this, it should be fine

n = int(input())
lst = []
for i in range(0, n):
  x = input() # no split as above comments 
  lst.append(x) 

# remove end part (no need for comparison
lst = sorted(lst, key=lambda x: x.lower().rsplit(".",1)[0])
print(lst)

# if you really need to split you can do 
for item in lst:
  item = item.split(".")
  # what is the point of this IF stateement ? (OP, please check the logic here )
  if item[0] == 'f':
    print(item[0], item[1].capitalize(), item[2])
  else:
    print(item[0], item[1].capitalize(), item[2])

Output :

f Mina C
f Sara java
m Ahmad C  
m Hossein python