replace '\\x' with '\x'-CodePudding

>>> s = '\\xca'
>>> s
'\\xca'
>>> s.replace('\\x', '\x')
  File "<stdin>", line 1
    s.replace('\\x', '\x')
                         ^
SyntaxError: (unicode error) 'unicodeescape' codec can't decode bytes in position 0-1: truncated \xXX escape

how to bypass the error? to print 'Ê' character instead of \\xca

PS: s.replace('\\xca', '\xca') is not what I want

CodePudding user response：

What you need to do is escape your '' characters in your replace so it's actually reading your \ as a \ instead of as an escape for the next character.

Example:

s = '\\xca'
s.replace('\\\\x', '\\x')
print(s)

CodePudding user response：

Simply change s='\\cxa' to s='\cxa' and it will print your desired character. This is because in the former string the first backslash escapes the second one and the last three characters are treated as normal text. While in the latter the three last characters are treated together.

To understand this in more detail you should look into "escape characters".