How to get a string between two other substrings from a string which includes quotes in python-CodePudding

I have the following string :

name: "gcr.io/myproject/github.com/project/project-1:9246b98256013b49"
digest: "sha256:9a9e3a4fb7072b7"
push_timing {
  start_time {
    seconds: 1660330436
    nanos: 983521156
  }
  end_time {
    seconds: 1660330706
    nanos: 296478248
  }
}

I just want to get the string after 'name : ' and the first following quote '"'. The answer string should be 'gcr.io/myproject/github.com/project/project-1:9246b98256013b49'

I have been trying to use the following command with no luck yet.

image_name = re.search(r'name : "(.*)"', image_info)

So how can I get a string between two other substrings from a string which includes quotes in python ?

CodePudding user response：

It looks like you're trying to match an extra space in regex.

This line:

image_name = re.search(r'name : "(.*)"', image_info)

is matching for something that starts with name :, while in your file, it starts with name:. Note the extra space.

An easy fix is to just remove the space.

image_name = re.search(r'name: "(.*)"', image_info)

As @KingsMMA mentioned in the comments, your file seems to be in the form of a JSON file. You can try parsing it as such, which means you can retrieve other elements of your file (like digest) much more easily.

CodePudding user response：

Always worthwhile checking return values. Also, using named groups can help to make the code more readable. For example:

import re

mystring = """
name: "gcr.io/myproject/github.com/project/project-1:9246b98256013b49"
digest: "sha256:9a9e3a4fb7072b7"
push_timing {
  start_time {
    seconds: 1660330436
    nanos: 983521156
  }
  end_time {
    seconds: 1660330706
    nanos: 296478248
  }
}"""

if (mo := re.search('name:\s "(?P<name>.*)"', mystring)):
    print(mo['name'])
else:
    print('Not found')

Output:

gcr.io/myproject/github.com/project/project-1:9246b98256013b49

CodePudding user response：

You can also use these lines for separating groups in a more complex structure:

search_string = r'name: "(.*)"'    
match_string = re.search(r'name: "(.*)"', image_info)

Then return your intended group:

image_name = match_string.group(1)

output:

gcr.io/myproject/github.com/project/project-1:9246b98256013b49

Note that using group(0) returns the whole regex matching part.