I am studying zsh on macOS and I find when adding software to $PATH you are usually supposed to write them in .zshrc (zsh). However, Visual Studio Code documentation suggests

To add VS Code to your path, to do so run the following commands:

cat << EOF >> ~/.zprofile
# Add Visual Studio Code (code)
export PATH="\$PATH:/Applications/Visual Studio Code.app/Contents/Resources/app/bin"
EOF

I find zprofile set the environment for login shells while zshrc sets the environment for interactive shells. However, I cannot really see differences between two methods on macOS terminal since each terminal tab is a login session on macOS by default. Is there any reason why Visual Studio Code on macOS suggests add $PATH to zprofile instead of zshrc and what will be the good practice?

CodePudding user response：

If you read this and this answer as well as the man page (man zsh under STARTUP/SHUTDOWN FILES) you might come to the following conclusion:

You are using MacOS, therefore every zsh you open is a login shell, that way you made sure, that .zprofile will always be read. So if you append your $PATH in your .zprofile and and use zsh as a non interactive-shell you will be able to access your appended $PATH. This might happen in a script of if other programs try to use a program that you added to your $PATH.

Now on the other hand if you added VSCode to your .zshrc it will always be available in an interactive shell. Which mean if you use VSCode 'manually' you will always have it at your disposal in zsh. But other programs/scripts might not find it.