How can i create a list of 50 random numbers where the even numbers are twice the odd numbers?-CodePudding

can you help me with this problem please? I have to create a list of 50 random numbers from 1 to 10 where the odd numbers frequency is aproximately twice the even number frequency.

CodePudding user response：

Try two list, one with 33 random odd numbers and the other with 17 random even numbers, and then merge the two lists.

CodePudding user response：

Solution as simplified

import random
odd=[item for item in range(1,11,2)]
even=[item for item in range(2,11,2)]
# twice chance 50/3 ~17   odd=33  even=17
random_even=[random.choice(even) for _ in range(17)]
random_odd=[random.choice(odd) for _ in range(33)]
random_number=random_even random_odd # sum 
random.shuffle(random_number) # messing up order
print("even",len(random_even),"odd",len(random_odd)) #check len
print("len list  : ",len(random_number))#check len
print(random_number)#show list