Invoking function from the 2d array of function pointers-CodePudding

#include <stdio.h>

void test1(){ printf("test1\n"); }
void test2(){ printf("test2\n"); }
void test3(){ printf("test3\n"); }
void test4(){ printf("test4\n"); }

void (*hv_ptr[2])() = {test1,test2};
void (*dev_ptr[2])() = {test3,test4};

void (**ptr[2])() = {hv_ptr, dev_ptr};

int main() {

   ptr[0][0];
   ptr[0][1];
   ptr[1][0];
   ptr[1][1];

   return 0;
}

I have declared the array of pointers to function pointers. But with this code, functions are not getting called. Kindly let me know what is going wrong here.

CodePudding user response：

ptr is an array of pointers to pointers to functions, so ptr[0] is a pointer to a pointer to a function, so ptr[0][0] is a pointer to a function.

Thus, in the expression statement ptr[0][0];, the expression is just a pointer to a function. It does not contain a function call.

ptr[0][0](); is a call to the function pointed to by ptr[0][0].