Inverse Regex matching street address-CodePudding

I'm trying to create a regex expression. I looked at this stackoverflow post and some others but I haven't been able to solve my problem.

I'm trying to match part of a street address. I want to capture everything after the directional.

Here are some examples

5XX N Clark St

91XX S Dr Martin Luther King Jr Dr

I was able to capture everything left of the directional with this pattern.

\d [X] \s\w

It returns 5XX N and 91XX S

I was wondering how I can take the inverse of the regex expression. I want to return Clark St and Dr Martin Luther King Jr Dr.

I tried doing

(?!\d [X] \s\w)

But it returns no matches.

CodePudding user response：

Use the following pattern :

import re
s1='5XX N Clark St'
s2='91XX S Dr Martin Luther King Jr Dr'
pattern="(?<=N|S|E|W).*"
k1=re.search(pattern,s1)
k2=re.search(pattern,s2)
print(k1[0])
print(k2[0])

Output:

Clark St
Dr Martin Luther King Jr Dr

CodePudding user response：

we do not need necessarily use regex to get the desired text from each line of the string:

text =["5XX N Clark St", "91XX S Dr Martin Luther King Jr Dr"]

for line in text:
    print(line.split(maxsplit=2)[-1])

result is:

Clark St
Dr Martin Luther King Jr Dr