I want to convert String's byte array to BigInteger and vis-versa.
I'm able to do this for some language specifically. For example:-
in java: new BigInteger("ab".getBytes())
and in dart: _convertBytesToBigInt(Uint8List.fromList(Utf8Encoder().convert('ab')))
where _convertBytesToBigInt()
method is from dartlang sdk's github issue discussion (here and here).
I tried coping the same code from dart to java:
BigInteger _convertBytesToBigInt(byte[] bytes) {
BigInteger result = BigInteger.ZERO;
for (byte z : bytes) {
// reading in big-endian, so we essentially concat the new byte to the end
result = (result.shiftLeft(8)).or(BigInteger.valueOf(z));
}
return result;
}
and this don't work when I try to perform simple multiplication/division in java (but it works in flutter however)
// in java:
byte[] x = writeBigInt(_convertBytesToBigInt(writeBigInt(_convertBytesToBigInt("ab".getBytes()).multiply(BigInteger.TEN))).divide(BigInteger.TEN));
//returns [-25, -6] but it should return [97,98]
//in dart:
Uint8List y = _writeBigInt(_convertBytesToBigInt(_writeBigInt(
_convertBytesToBigInt(
Uint8List.fromList(const Utf8Encoder().convert('ab'))) *
BigInt.two)) ~/
BigInt.two);
//it returns [97,98] which is expected result.
I tried copying Java's BigInteger class and it's toByteArray()
method but again, it don't work with dart properly.
These methods works normally if I try without multiplication/division, so only possible thing is, they both multiply/divide in different way if I'm not wrong.
Is there ANY solution for this? So that I can turn byte arr to BigInteger in ANY language (specifically popular ones like Java, Dart/flutter, Rust, Python, JS, etc).
NOTE:
Following are the methods which I used in dart and java respectively.
BigInt _convertBytesToBigInt(Uint8List bytes) {
BigInt result = BigInt.zero;
for (final byte in bytes) {
// reading in big-endian, so we essentially concat the new byte to the end
result = (result << 8) | BigInt.from(byte);
}
return result;
}
Uint8List _writeBigInt(BigInt number) {
// Not handling negative numbers. Decide how you want to do that.
int bytes = (number.bitLength 7) >> 3;
var b256 = BigInt.from(256);
var result = Uint8List(bytes);
for (int i = 0; i < bytes; i ) {
result[i] = number.remainder(b256).toInt();
number = number >> 8;
}
return result;
}
BigInteger _convertBytesToBigInt(byte[] bytes) {
BigInteger result = BigInteger.ZERO;
for (byte z : bytes) {
// reading in big-endian, so we essentially concat the new byte to the end
result = (result.shiftLeft(8)).or(BigInteger.valueOf(z));
}
return result;
}
static byte[] writeBigInt(BigInteger number) {
// Not handling negative numbers. Decide how you want to do that.
int bytes = (number.bitLength() 7) >> 3;
BigInteger b256 = BigInteger.valueOf(256);
byte[] result = new byte[bytes];
for (int i = 0; i < bytes; i ) {
result[i] = (byte) Integer.parseInt(number.remainder(b256).toString());
number = number.shiftRight(8);
}
return result;
}
CodePudding user response:
In Java a byte is a signed 8-bit value (ranges from -128 to 127). To get an unsigned value, you can bitwise AND it with 255. Try
BigInteger _convertBytesToBigInt(byte[] bytes) {
BigInteger result = BigInteger.ZERO;
for (byte z : bytes) {
result = (result.shiftLeft(8)).or(BigInteger.valueOf(z & 0xff));
}
return result;
}
Side note regarding writeBigInt
: just use Number#byteValue()
instead of toString()
and parseInt()
.
Udate
_convertBytesToBigInt() assumes the bytes to be given in big-endian whereas writeBigInt writes little-endian. Here's a corrected version for that, too:
byte[] writeBigInt(BigInteger number) {
// Not handling negative numbers. Decide how you want to do that.
int bytes = (number.bitLength() 7) >> 3;
BigInteger b256 = BigInteger.valueOf(256);
byte[] result = new byte[bytes];
for (int i = 0; i < bytes; i ) {
result[bytes-1-i] = number.remainder(b256).byteValue();
number = number.shiftRight(8);
}
return result;
}