I am working on a project and I need to be able to create a function that takes in a value (n) and returns a matrix with increasing values.

ex: Given x = 2, return = [[1],[1, 2]]

Given x = 5, return = [[1], [1, 2], [1, 2, 3], [1, 2, 3, 4],[1, 2, 3, 4, 5]]

Below is what I have thus far:

def matrixIncrease(n):
    lst = []
        
    for i in range(n):
        lst.append([])
        for j in range(0, n):
            lst[i].append(j)
    return lst

print(matrixIncrease(3))

This will just return

[[0, 1, 2], [0, 1, 2], [0, 1, 2]]

So it looks like the correct amount of inner list are being created. But, the values inside the list are not increasing correctly. Any suggestions?

CodePudding user response：

Maybe you could try this List Comprehension way:

It's quite self-explnatory in the code, just play/experiment with different i and j to see the effects of changes...

Basically the j is to iterate and increase the numbers in each loop.

def create_sub(n):
    ''' create n sub_lists: each list has increasing items:
        [1], [1, 2], [1, 2, 3], .... [1, ... n] '''
    sub_matrix = [[j  1 for j in range(0, i)]        # j - for col values
                        for i in range(1, n   1)]    # i - control rows
    return sub_matrix

>>>create_sub(5)
[[1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 3, 4, 5]]

>>>create_sub(8)
[[1], [1, 2], [1, 2, 3], [1, 2, 3, 4], [1, 2, 3, 4, 5], [1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 5, 6, 7], [1, 2, 3, 4, 5, 6, 7, 8]]

CodePudding user response：

You could try this:

all_ = []
def matrixIncrease(n):
    if n == 1:
        all_.append([1])
        return[1]
    j=[]
    for i in range(1,n 1):
        j.append(i)
    matrixIncrease(n-1)
    all_.append(j)
  

matrixIncrease(7)
print(all_)