How to use "pop" method on zip() python-CodePudding

I need to write a function that return the first tuple of a zip object, and than deletes this tuple. The object may contain several identical tuples, so using list comprehension is problematic - because I can't remove ANY tuple that is equivalent to the tuple I need to remove.

Thanks for your time reading and willing to help!

CodePudding user response：

Simple you just have to convert it to a list

languages = ['Java', 'Python', 'JavaScript']
versions = [14, 3, 6]

result = zip(languages, versions)
result_list = list(result)
print("old:", result_list)
result_list.pop()
print("new:", result_list)

Does this answer your question?

CodePudding user response：

taking the sample from ss3387, we can generate the list directly when using zip(). this list can be sliced, so that we don’t need any further step.

languages = ['Java', 'Python', 'JavaScript']
versions = [14, 3, 6]
result = list(zip(languages, versions))[1:]
print(result)

CodePudding user response：

Start with two lists (this code will support more than 2 lists) e.g.,

listA = ['colour', 'make', 'type']
listB = ['red', 'Ford', 'saloon']

Now write a function that calls zip to acquire a tuple representing the first elements from each of the lists (of course using zip for this is unnecessary but for some reason known only to OP is a requirement)

def get_tuple_and_remove(*args):
    t = next(zip(*args))
    for arg in args:
        arg.pop(0)
    return t

Now...

print(get_tuple_and_remove(listA, listB))

print(listA)
print(listB)

Output:

('colour', 'red')
['make', 'type']
['Ford', 'saloon']

The same functionality could be achieved without zip like this:

def get_tuple_and_remove(*args):
    return tuple(a.pop(0) for a in args)