How to update dictionary keys that represent the number of times a letter appears in the user's-CodePudding

For example, I am trying to count the amount of times a letter appears in my input. Also, I'm trying to use the tools I've learned so far. I haven't learned the .count tools in the course I'm taking so far.

1st I run this code:

any_word = input()
char_amount = {}

for i in any_word:
    char_amount[i] = len(i)

print(char_amount)

My input is: hello

The result is this: I get every time is below and my if statements fail to update the key for 'l' to 2.

{'h': 1, 'e': 1, 'l': 1, 'o': 1}

My if statements fail to update the key for 'l' to 2. I cant figure out the logic to an if statement to add 1 to the 'l' key because the duplicate is recognized in every key and the result is below. I assume i need another variable but i can't think up the logic. Thanks for any help:

{'h': 2, 'e': 2, 'l': 2, 'o': 2}

CodePudding user response：

You should really be using the Counter class from the collections module:

from collections import Counter

value = input('Enter some text: ')

counter = Counter(value)

print(counter)

Thus, for an input of 'hello' you'd get:

Counter({'l': 2, 'h': 1, 'e': 1, 'o': 1})

Counter subclasses dict so you can access it just like any other dictionary

CodePudding user response：

Use char_amount[i] = char_amount.get(i, 0) 1 - this will try to get key i from dict char_amount, if not found returns 0. Then increases the value of this key by 1

any_word = input()
char_amount = {}

for i in any_word:
    char_amount[i] = char_amount.get(i, 0)   1

print(char_amount)

Prints:

hello
{'h': 1, 'e': 1, 'l': 2, 'o': 1}

CodePudding user response：

Without collections Module:

word = input()
char_amount = {}

for char in word:
    if char not in char_amount:
        char_amount[char] = 1
    else:
        char_amount[char]  = 1

print(char_amount)

Using collections module:

from collections import Counter

print(Counter(input()))

CodePudding user response：

use built in counter

from collections import Counter

my_counter = Counter("hello")
print(my_counter)

Counter({'l': 2, 'h': 1, 'e': 1, 'o': 1})