I recently stumbled upon the following behavior in MATLAB R2022a:
>> a = sparse(1,2,1)
a =
(1,2) 1
>> b = sparse(2,1,18)
b =
(2,1) 18
>> a b
ans =
(2,1) 18
(1,2) 1
(2,2) 19
The presence of the (2,2) element with value 19 is quite puzzling. Intuitively, I would have expected to get either a zero (no element) or an error indicating that the vectors' sizes are not compatible. I couldn't find an explanation for this behavior in the documentation.
So, is this a bug or a feature?
CodePudding user response:
This is due to implicit broadcasting and expected behaviour, also for full()
arrays. Compare:
bsxfun(@plus, [0 1], [0; 18])
ans =
0 1
18 19
(I'm running R2007b, so need bsxfun()
instead of implicit broadcasting).
What happens with unequal-sized vectors is that they are "extended" into the appropriate size for addition, see this blog post on an in-depth explanation. In our toy example a
is broadcast to [0, 1; 0, 1]
and b
to [0, 0; 18, 18]
, resulting in what you see as answer when each element is added to its equivalent index in the other matrix.
CodePudding user response:
This is in fact similarly happening with full arrays, i.e. not restricted to sparse vectors, and this is normal behavior according to the documentation (see the Add Row and Column Vector section).