Lambda function to flip bits(1 to 0 and 0 to 1) in binary-CodePudding

I have been solving hackerrank problems, and currently in a problem where I'm supposed to convert the number to binary, reverse each digit.

Let's say there's an integer n, I convert it to binary using:

g = '{0:032b}'.format(n)

Now I have reversed 0s and 1s using the normal for loop, but, I would like to do the same using lambda function and/or the one-line for loop.

I have tried doing so like:

f = [lambda x: x = '1' if x == '0' else x = '1']
res = [f(x) for x in g]

and

res = [x = '1' for x in n if x == '0' else x = '0']

But I don't seem to get the syntax right. Also, if there's other better and shorter ways, kindly do enlighten me.
Any help would be appreciated!

CodePudding user response：

You can do like this,

In [1]: l = ["0", "1", "0", "0", "1"]
In [2]: f = lambda x: "1" if x == "0" else "0"
In [3]: [f(i) for i in l]
Out[3]: ['1', '0', '1', '1', '0']

Assigning lambda is a bad practice you could use a function itself.

In [4]: def f(x):
     ...:     if x == "0":
     ...:         return "1"
     ...:     else:
     ...:         return "0"

In [5]: [f(i) for i in l]
Out[5]: ['1', '0', '1', '1', '0']