Python split a string between different delimiters-CodePudding

I would like to split a string like this

str = "$$Node_Type<block=begin>Blabla$$Node_Type<block=end>"

to something like this:

tab = ["$$Node_Type<block=begin>", "Blabla", "$$Node_Type<block=end>"]

but I can also have this:

str = "$$Node_Type1<block=begin>Blabla1$$Node_Type2<block=begin>Blabla2$$Node_Type2<block=end>$$Node_Type1<block=end>"

to something like this:

tab = ["$$Node_Type1<block=begin>", "Blabla1", "$$Node_Type2<block=begin>", "Blabla2", "$$Node_Type2<block=end>", "$$Node_Type1<block=end>"]

The idea at the end is to print it like that

$$Node_Type1<block=begin>
   Blabla1
   $$Node_Type2<block=begin>
      Blabla2
   $$Node_Type2<block=end>
$$Node_Type1<block=end>

Does someone has an idea ? Thx

CodePudding user response：

You can take advantage of the fact that re.split retains the "splitter" in the results if it's a capturing group, and then:

import re

example = "Hello$$Node_Type1<block=begin>Blabla1$$Node_Type2<block=begin>Blabla2$$Node_Type2<block=end>$$Node_Type1<block=end>"

level = 0
for bit in re.split(r'(\$\$[^>] >)', example):
    if bit.startswith('$$') and bit.endswith('block=end>'):
        level -= 1
    if bit:
        print('  ' * level   bit)
    if bit.startswith('$$') and bit.endswith('block=begin>'):
        level  = 1

This prints out

Hello
$$Node_Type1<block=begin>
  Blabla1
  $$Node_Type2<block=begin>
    Blabla2
  $$Node_Type2<block=end>
$$Node_Type1<block=end>