how can i create this specific text file using python? (details down below)-CodePudding

I want a text file that has every variation of xxxxx-xxxxx (x is a number) so I want to create a text file that goes 00000-00000 00000-00001 00000-00002 00000-00003 etc... how can I do that with python?

CodePudding user response：

You can do it using a nested loop like this:

pattern = '00000-00000'
stack = []

for i in range(100000):
    for j in range(100000):
        num = pattern[:5-len(str(i))] str(i)   pattern[5]   pattern[6:-len(str(j))] str(j)
        stack.append(num)

***Just don't run this code. It will break your computer.

CodePudding user response：

The trick is to use .zfill(n) if you want to append "n" zeros before some integers. So, if you have i = 1 but you want to print it like 00001, you can you the following code:

print(str(i).zfill(5))

And as to your question, the solution is:

with open("output.txt", "a") as f:

    for i in range(100000):
        for j in range(100000):
            my_str = str(i).zfill(5)   "-"   str(j).zfill(5)   "\n"
            f.write(my_str)

    f.close()

Note: This will take a while to complete.

CodePudding user response：

Try this.

lst = []

s = '0000000000'

for a in range(10000):
    l = list(s   str(a))[-10:]
    l.insert(4,'-')
    lst.append(''.join(l) '\n')


with open('name.txt','w') as file:
    file.writelines(lst)