How to return array element whose first index is the largest number in JS?-CodePudding

Given the array below, how I can return the element whose first index contains the highest number:

let ar = [[1,24], [2, 6]]

I've tried many proposed solutions, but they return the number itself, while it should be, in the case above [2,6]

One of the solutions I've tried is, but it returns 24, 6:

var maxRow = arr.map(function(row){ return Math.max.apply(Math, row); });

CodePudding user response：

To do what you require you can use reduce() to compare the values of the first item in each child array and return the one with the highest value:

let ar = [[1,24], [2, 6]]
let result = ar.reduce((acc, cur) => acc[0] < cur[0] ? cur : acc);  
console.log(result);

CodePudding user response：

One way is using a reduce. Try like this:

const ar = [
  [1,24],
  [2, 6],
];

const biggest = ar.reduce(
  (acc, cur) => cur[0] > (acc?.[0] || 0) ? cur : acc,
  [],
);

console.log(biggest);