Replace string using MAP and LAMBDA in Python-CodePudding

I have a dataframe column called 'event' in a dataframe called 'calendar'. Obviously it contains event names and I want to replace those names by a single string. To do so, I use a few filters based on the content of the event names.

For instance, I want to replace all the names containing 'BoE','BoC','Fed', 'ECB' ,'RBA' or 'RBNZ' and also contain the word 'Speak' by simply 'Speak'.

To achieve that, I made this code:

banks=['BoE','BoC','Fed', 'ECB' ,'RBA','RBNZ']
calendar['event'] = list(map(lambda x : 'Speak' if any(bancs) and 'Speak' in x else x, calendar['event']))

Most of times it works fine, but I usally get the error: 'DataFrame' object is not callable'. I guess there's something wrong in the syntax so I'll be thankfull with any correction or any alternative code that can be useful

CodePudding user response：

Your current code seems to have both typos and logical errors (e.g. your use of any).
Try this -

banks=['BoE','BoC','Fed', 'ECB' ,'RBA','RBNZ']
calendar['event'] = list(map(lambda x : 'Speak' if (any([b in x for b in banks]) and 'Speak' in x) else x, calendar['event']))

Testing on a simple example:

calendar = pd.DataFrame(columns=['event'])
calendar['event'] = ['Speak BoC', 'BoE', 'Speak Q', 'RBNZSpeak']  # Only 1st and 3rd should be replaced by "Speak"
banks=['BoE','BoC','Fed', 'ECB' ,'RBA','RBNZ']
calendar['event'] = list(map(lambda x : 'Speak' if (any([b in x for b in banks]) and 'Speak' in x) else x, calendar['event']))
print(calendar.event)
# 0      Speak
# 1        BoE
# 2    Speak Q
# 3      Speak

But none of your typos/mistakes seem to relate to your error, so there might be problems elsewhere in your code.
You should post an error-producing example if the answers here don't address your problem.