Pyside6 respond to keyboard input-CodePudding

I'm using Pyside6

I want to change what widgets show in reaction to keyboard inputs from the user.

The minimum helpful example would be just a label that shows 1-5 depending on which number key the user presses.

My attempt (nothing gets printed, so I guess this is never called and I have to attach it to something):

    def keyPressEvent(self, event):
        key = event.key()
        print(f"Found key {key}")
        if key == QtCore.Qt.Key_1:
            self.selected_bin = 1
            self.set_current_bin()
        elif key == QtCore.Qt.Key_2:
            self.selected_bin = 2
            self.set_current_bin()
        elif key == QtCore.Qt.Key_3:
            self.selected_bin = 3
            self.set_current_bin()
        elif key == QtCore.Qt.Key_4:
            self.selected_bin = 4
            self.set_current_bin()
        elif key == QtCore.Qt.Key_5:
            self.selected_bin = 5
            self.set_current_bin()
        else:
            super(self).keyPressEvent(event)

    def set_current_bin(self):
        self.ui.current_bin.setText(f"Current bin: {self.selected_bin}")

I feel like this is super simple, but I've searched for about half an hour with no luck.

CodePudding user response：

Your example works fine in PySide2 except for having to change

super(self).keyPressEvent(event)

super().keyPressEvent(event)

in your else block.

This is my test for you to test on PySide6 to see if the veriso nis the issue:

from PySide2 import QtCore, QtWidgets

class TestWidget(QtWidgets.QLabel):
    
    def keyPressEvent(self, event):
        key = event.key()
        print(f"Found key {key}")
        if key == QtCore.Qt.Key_1:
            self.selected_bin = 1
            self.set_current_bin()
        elif key == QtCore.Qt.Key_2:
            self.selected_bin = 2
            self.set_current_bin()
        elif key == QtCore.Qt.Key_3:
            self.selected_bin = 3
            self.set_current_bin()
        elif key == QtCore.Qt.Key_4:
            self.selected_bin = 4
            self.set_current_bin()
        elif key == QtCore.Qt.Key_5:
            self.selected_bin = 5
            self.set_current_bin()
        else:
            super().keyPressEvent(event)
    
    def set_current_bin(self):
        self.setText(f"Current bin: {self.selected_bin}")
        
if __name__ == '__main__':
    
    import sys
    args = sys.argv
    app = QtWidgets.QApplication(args)
    w = TestWidget("Testing")
    w.show()
   
    sys.exit(app.exec_())

CodePudding user response：

Install an event filter that listens for key presses and then set the label text to the event's key text value.

Here is a working example:

from PySide6.QtWidgets import *
from PySide6.QtCore import *
from PySide6.QtGui import *

class Window(QWidget):

    def __init__(self, parent=None):
        super().__init__(parent=parent)
        self.layout = QHBoxLayout(self)
        self.label1 = QLabel("", self)
        self.label2 = QLabel("Key Pressed: ", self)
        self.layout.addWidget(self.label2)
        self.layout.addWidget(self.label1)
        self.resize(100,50)
        self.eventFilter = KeyPressFilter(parent=self)
        self.installEventFilter(self.eventFilter)

class KeyPressFilter(QObject):

    def eventFilter(self, widget, event):
        if event.type() == QEvent.KeyPress:
            text = event.text()
            if event.modifiers():
                text = event.keyCombination().key().name.decode(encoding="utf-8")
            widget.label1.setText(text)
        return False



if __name__ == '__main__':
    app = QApplication([])
    window = Window()
    window.show()
    app.exec()