I want to decode a string (which I got via readAsDataUrl()
) to bytes.
At first, I remove the data:*/*;base64
, then I call the following:
Option Explicit
Private Const CRYPT_STRING_BASE64 As Long = &H1&
Private Declare Function CryptStringToBinaryW Lib "Crypt32.dll" ( _
ByVal pszString As Long, _
ByVal cchString As Long, _
ByVal dwFlags As Long, _
ByVal pbBinary As Long, _
ByRef pcbBinary As Long, _
ByVal pdwSkip As Long, _
ByVal pdwFlags As Long) As Long
Public Function DecodeBase64(ByVal strData As String) As Byte()
Dim Buffer() As Byte
Dim dwBinaryBytes As Long
dwBinaryBytes = LenB(strData)
ReDim Buffer(dwBinaryBytes - 1) As Byte
'within the following call, VB6 crashes:
If CryptStringToBinaryW(StrPtr(strData), LenB(strData), CRYPT_STRING_BASE64, _
VarPtr(Buffer(0)), dwBinaryBytes, 0, 0) Then
ReDim Preserve Buffer(dwBinaryBytes - 1) As Byte
DecodeBase64 = Buffer
End If
Erase Buffer
End Function
Now I call this:
Dim s$
'code to get base64 string
'code to strip for example "data:image/jpeg;base64,"
Dim nBytes() As Byte
nBytes = DecodeBase64(s) 'Here VB6 crashes
Edit:
I am using the following alternative version now, and it works, but I wonder what the error is:
Public Function DecodeBase64(ByVal sBase64Buf As String) As Byte()
Const CRYPT_STRING_BASE64 As Long = 1
Const CRYPT_STRING_NOCRLF As Long = &H40000000
Dim bTmp() As Byte
Dim lLen As Long
Dim dwActualUsed As Long
'Get output buffer length
If CryptStringToBinary(StrPtr(sBase64Buf), Len(sBase64Buf), CRYPT_STRING_BASE64, StrPtr(vbNullString), lLen, 0&, dwActualUsed) = 0 Then
'RaiseEvent Error(Err.LastDllError, CSB, Routine)
GoTo ReleaseHandles
End If
'Convert Base64 to binary.
ReDim bTmp(lLen - 1)
If CryptStringToBinary(StrPtr(sBase64Buf), Len(sBase64Buf), CRYPT_STRING_BASE64, VarPtr(bTmp(0)), lLen, 0&, dwActualUsed) = 0 Then
'RaiseEvent Error(Err.LastDllError, CSB, Routine)
GoTo ReleaseHandles
Else
'm_bData = bTmp
End If
ReleaseHandles:
DecodeBase64 = bTmp
End Function
Edit:
In version 1, dwBinaryBytes
is 156080 in this line:
dwBinaryBytes = LenB(strData)
and in version 2, lLen is 58528 in this line:
ReDim bTmp(lLen - 1)
Why the discrepancy, and why didn't the author notice that?
CodePudding user response:
The "CryptStringToBinaryW" requires the number of characters in the string as a parameter. That is returned by the "Len" function. You used the "LenB" function which returns the number of bytes in the string which is larger than the number of characters in the string so the function attempted to access memory past the end of the string which caused the crash.