How do you use %random% to pick a numbered variable?-CodePudding

I want to use %random% %8 to pick a random variable from a number of variables called "song1" through "song118" Here's my current code:

@ECHO off
TITLE Music Randomize
SET count=0
GOTO cont

:func
ECHO %1
SET /A count =1
SET "song%count%=%1"
GOTO :eof

:cont
FOR %%F IN (C:\Users\153651\Desktop\usic\*) DO CALL :func "%%F"

ECHO %song%random% %8  1%
PAUSE

Right now the last ECHO command gives me the output "random18 1". How can I get it to output a random one of the variables?

CodePudding user response：

I'm a little confused by what your problem is.

As an example, this works:

set SONG=TaylorSwift

REM Choose a random number between 1 and 118
set /a SONGNUM=%RANDOM% * 118 / 32768   1

REM Here's the random song name:
set MYSONG=%SONG%%SONGNUM%
echo %MYSONG%

REM Prints: TaylorSwift9 (if "9" was the random number)

I think you might have a mismatch in how your % signs are aligned, but I'm struggling to understand the aims of your code.

CodePudding user response：

There are a few minor errors in your code:

Arithmetic works only with set /a, so you need to pre-calculate the value before using it
you should use %~1 to remove the quotes
to use a "variable within a variable", you need either delayed expansion or another trick to force a second instance of parsing (I decided not to use delayed expansion, because there might be ! in your files (think P!nk for example))

The corrected code could look like this:

@ECHO off
setlocal 
TITLE Music Randomize
SET count=0
GOTO cont

:func
rem ECHO %1
SET /A count =1
SET "song%count%=%~1"
GOTO :eof

:cont
FOR %%F IN (C:\Users\153651\Desktop\usic\*) DO CALL :func "%%F"
set /a rnd=%random% %8  1
call ECHO %%song%rnd%%%
pause