I have a string that contains a random amounts of numbers, these numbers can be like 1, 2, 3 and so, but they can even be 100, 20, 25... so if I'm searching for 14, I will find a 14 in 144, if the string contains it. I Have to split them into a list of integers. Here's what I tried:
def to_list(string):
result_list = []
for idx in range(len(string)):
if string[idx] != "0":
zeros = 0
for j in string[idx 1:len(string)]:
if j == "0":
zeros = 1
else:
result_list.append(string[idx] "0" * zeros)
break
result_list.append(string[-1])
return result_list
CodePudding user response:
You can use regex for that
import re
a = "1001010050101"
a = list(map(int, re.findall(r"[1-9] 0*", a)))
print(a)