Splitting a sequence of number into a list (Python)-CodePudding

I wanted to ask you how can I split in Python for example this string '20020050055' into a list of integer that looks like [200, 200, 500, 5, 5].

I was thinking about enumerate but do you have any example of a better solution to accomplish this example? thanks

CodePudding user response：

One approach, using a regex find all:

inp = '20020050055'
matches = re.findall(r'[1-9]0*', inp)
print(matches)  # ['200', '200', '500', '5', '5']

If, for some reason, you can't use regular expressions, here is an iterative approach:

inp = '20020050055'
matches = []
num = ''
for i in inp:
    if i != '0':
        if num != '':
            matches.append(num)
        num = i
    else:
        num = num   i
matches.append(num)

print(matches)   # ['200', '200', '500', '5', '5']

The idea here is to build out each match one digit at a time. When we encounter a non zero digit, we start a new match. For zeroes, we keep concatenating them until reaching the end of the input or the next non zero digit.