I am currently learning python and i cant seen to figure out how to get a if - then statement for a dice to work (randomint).

I tried

if roll_dice < 10:
  print ("dang, you got a low roll, try again")
else:
  roll_dice > 10
  print ("nice! you got a high roll")
  roll_dice = 10
  print ("10!")

It says "ValueError: don't know how to compare 'function' and 'int' "

CodePudding user response：

Maybe you want it to work this way:

if roll_dice < 10:
  print ("dang, you got a low roll, try again")
elif roll_dice > 10:
  print ("nice! you got a high roll")
else:
  print ("10!")

or

if roll_dice < 10:
  print ("dang, you got a low roll, try again")
elif roll_dice > 10:
  print ("nice! you got a high roll")
elif roll_dice == 10:
  print ("10!")

CodePudding user response：

Sounds like roll_dice is a function, so you need to call it to get an answer, so roll_dice < 10 is meaningless. It would be like asking print < 10 or abs < 10.

Try this:

roll = roll_dice()
if roll < 10:
    print("dang, you got a low roll, try again")
elif roll > 10:
    print ("nice! you got a high roll")
else:
    assert(roll == 10)
    print("10!")

CodePudding user response：

Here's another version of the code in one line - using the ternary operator. This sort of coding is not advised, but illustrates another way of coding this.

print ("dang, you got a low roll, try again" if roll_dice < 10 else "nice! you got a high roll" if roll_dice > 10 else "10!" )

The real issue with the original question is that the syntax of the if statement is incorrect.

CodePudding user response：

I don't know how you are feeding your variable (roll_dice). But if it's through a keyboard input you can do this.

Code to look at

Remember also to compare a roll_dice >10.

You have to do this int(roll_dice).

It changes it from string to integer.