Regex to find and replace spaces within pattern-CodePudding

I have the following string:

"data-template='Test xxx' root{--primary-font:'XYZ Sans';--secondary-font:'Test Sans';--hero-background:#ffbe3f;--header-colour-highlight:#f0591e;--header-background:#ffffff;--header-colour-tabs:#1d2130; }"

I need to replace the spaces from -font:'XYZ Sans' and -font:'Test Sans' in order to make it -font:'XYZSans' and -font:'TestSans'

Edit: the text inside the -font: may change it is not static.

Could anyone help with that?

CodePudding user response：

Try this:

(?<=XYZ) (?=Sans)|(?<=Test) (?=Sans)

EDIT: This is another regex pattern will match the value of -front: and removes any spaces between strings, it is dynamic.

(?<=-font:\s*['\x22][^'\x22] ?)\s(?=[^'\x22]*)

"data-template='Test xxx' root{--primary-font:'XYZ Sans';--secondary-font:'Test Sans';--hero-background:#ffbe3f;--header-colour-highlight:#f0591e;--header-background:#ffffff;--header-colour-tabs:#1d2130; }"

1- (?<=XYZ) (?=Sans) match a space proceeded by XYZ but do not include XYZ as a part of that match, at the same time the space should be followed by Sans, but don't include Sans as a part of the match, we only want the space . This part will match the first space between XYZ Sans

2- | the alternation operator | , it is like Boolean OR If the first part of the regex(i.e., the pattern before |) matches a space , the second part of the regex(i.e., the pattern after |) will be ignored, this is not what we want because of that we have to add g modifier which means get all matches and don't return after first match.

3- (?<=Test) (?=Sans) match a space proceeded by Test but do not include Test as a part of that match, at the same time the space should be followed by Sans, but don't include Sans as a part of the match, we only want the space. This part will match the second space between Test Sans

See live demo.

The C# code that does what you want is something like this:

Note: I updated the regex pattern in the code.


using System;
using System.Text.RegularExpressions;

public class Example
{
   public static void Main()
   {
      string input = "\"data-template='Test xxx' root{--primary-font:'XYZ Sans';--secondary-font:'Test Sans';--hero-background:#ffbe3f;--header-colour-highlight:#f0591e;--header-background:#ffffff;--header-colour-tabs:#1d2130; }\"";
      string pattern = @"(?<=-font:\s*['\x22][^'\x22] ?)\s(?=[^'\x22]*)";
      string replacement = "";
      string result = Regex.Replace(input, pattern, replacement);
      
      Console.WriteLine("Original String: {0}", input);
      Console.WriteLine("\n\n-----------------\n\n");
      Console.WriteLine("Replacement String: {0}", result);                             
   }
}