I've this:

"example: myresult"

And I need a method that looks for this from ": "

"myresult"

I tried with String.search()

CodePudding user response：

use string.includes(searchString, position), that have a second param of position to start the search.

position Optional The position within the string at which to begin searching for searchString. (Defaults to 0.)

const str = "example: myresult";
const startIndex = str.indexOf(': ');
console.log(str.includes('example')); // true
console.log(str.includes('example', startIndex)); // false
console.log(str.includes('myresult', startIndex)); //true

CodePudding user response：

this should work

function getSecondPart(str) {
    return str.split(':')[1];
}

CodePudding user response：

As a last resort you have also the regular expression route to extract the value following semicolons preceded by a label:

const subject = "example: myresult";
const re = /^. ?\: (. )$/im;
const match = re.exec(subject);
let result = "";
if (match !== null) {
    result = match[1];  
}

console.log(result);

CodePudding user response：

Assuming the ": " is always consistent this should work for you:

  var myresult = "example: myresult";
  console.log(myresult.split(': ')[1]);

CodePudding user response：

try

'string'.includes(':')

you can check if the symbol or letter is in the word by includes in the words