I want to do correlations for each unique combination and grouped by another variable. My solutions works for a very small dataset buy imagine more columns it's getting very tedious.
set.seed((13))
df <- data.frame(group = rep(LETTERS[1:3], 3),
var1 = rnorm(9, 1),
var2 = rnorm(9, 2),
var3 = rnorm(9, 1))
df %>%
group_by(group) %>%
summarise(var1_var2 = cor(var1, var2),
var1_var3 = cor(var1, var3),
var2_var3 = cor(var2, var3))
I also tried this one, but it doens't work.
df %>%
group_by(group) %>%
summarise(cor = cor(df[,2:ncol(df)]))
CodePudding user response:
Here is an option. Map out all the combos then run a cor test for each group and each var and then pivot wider at the end:
library(tidyverse)
map_dfr(unique(df$group), \(x){
data.frame(t(combn(c("var1", "var2", "var3"), 2))) |>
mutate(group = x)
}) |>
mutate(cor = pmap_dbl(list(X1, X2, group),
~cor(df[df$group == ..3, ..1],
df[df$group == ..3, ..2]))) |>
unite(test, X1, X2) |>
pivot_wider(names_from = test, values_from = cor)
#> # A tibble: 3 x 4
#> group var1_var2 var1_var3 var2_var3
#> <chr> <dbl> <dbl> <dbl>
#> 1 A 0.318 -0.476 -0.985
#> 2 B -0.373 -0.487 -0.628
#> 3 C 0.535 0.991 0.645
CodePudding user response:
Another solution. This works for any number of variables.
library(dplyr)
library(tidyr)
library(purrr)
library(tibble)
set.seed((13))
df <- data.frame(group = rep(LETTERS[1:3], 3),
var1 = rnorm(9, 1),
var2 = rnorm(9, 2),
var3 = rnorm(9, 2))
df %>%
select(-group) %>%
split(df$group) %>%
imap_dfr(
~ {
expand.grid(
first = names(.x),
second = names(.x),
stringsAsFactors = FALSE
) %>%
filter(first < second) %>%
rowwise() %>%
transmute(
group = .y,
pair = paste(first, second, sep = "_"),
cor = cor(.x[[first]], .x[[second]])
)
}
) %>%
pivot_wider(
names_from = "pair",
values_from = "cor"
)
# # A tibble: 3 × 4
# group var1_var2 var1_var3 var2_var3
# <chr> <dbl> <dbl> <dbl>
# 1 A 0.318 -0.476 -0.985
# 2 B -0.373 -0.487 -0.628
# 3 C 0.535 0.991 0.645