Need some help about template member function specialization as following code;

class Base
{
    public:
        template <int>  void MyFunc();
};


class Object : public Base
{
    public:
        //template <int>    void MyFunc(); // with this works !!!

        template <> void MyFunc<3>()
        {
        }
};

Thanks !!!

CodePudding user response：

You can't.

The reason is that when the compiler sees the declaration of Object, it doesn't know anything about Base's template functions. So it can't generate a specialization of MyFunc for Object.

The only way to make this work is to declare the specialization of MyFunc in the Base class.

Member function templates are not inherited.