Check if an specific file available or not in a directory-CodePudding

File_Name = "Invoice_Dmart"
Folder-Name = "c:\Documents\Scripts\Bills"

How to check if the specific filename exist in the "Folder-Name" with any extension, If Yes Get the full path in a variable.

Code i have been using:

import os.path
if not os.path.Folder-Name(File_Name):
      print("The File s% it's not created "%File_Name)
      os.touch(File_Name)
      print("The file s% has been Created ..."%File_Name)

Please Suggest the best possible way to solve it.

CodePudding user response：

I would use pathlib.Path here. It provides convenient apis to iterate over the directories(.iterdir()) and also to get the filename without extension(.stem). So you can do somewhat like this.

>>> from pathlib import Path
>>> [str(child) for child in Path(your_folder_name).iterdir() if child.stem == your_file_name]

CodePudding user response：

try the code below

import os

file_name = "Invoice_Dmart"
folder_name = "c:\Documents\Scripts\Bills"

# os.path.splitext() split filename and ext
# os.listdir() list all files in the given dir
filenames_wo_ext = [os.path.splitext(elem)[0] for elem in os.listdir(folder_name)]
if file_name not in filenames_wo_ext:
    print("The File %s it's not created "% file_name)
    with open(file_name, 'w'):
        print("The file %s has been Created ..."% file_name)

CodePudding user response：

Before, you should fix the syntax of the variable Folder-Name to Folder_Name.

I guess you can solve the problem by simply adding the two strings through a slash, and using the function os.path.exists() like:

import os.path

File_Name = "Invoice_Dmart"
Folder_Name = "c:\Documents\Scripts\Bills"

path = Folder_Name   "\"   File_Name       

exist = os.path.exists(path)
print(exist)

It worked for me, hope it does for you aswell.