In Python, if I do this:
print "4" * 4
I get
> "4444"
In Perl, I'd get
> 16
Is there an easy way to do the former in Perl?
CodePudding user response:
$ perl -e 'print "4" x 4; print "\n"'
4444
The x operator is documented in perldoc perlop. Here binary means an operator taking two arguments, not composed of bits, by the way.
Binary "x" is the repetition operator. In scalar context or if the left operand is not enclosed in parentheses, it returns a string consisting of the left operand repeated the number of times specified by the right operand. In list context, if the left operand is enclosed in parentheses or is a list formed by "
qw/STRING/
", it repeats the list. If the right operand is zero or negative, it returns an empty string or an empty list, depending on the context.
print '-' x 80; # Print row of dashes
print "\t" x ($tab/8), ' ' x ($tab%8); # Tab over
@ones = (1) x 80; # A list of 80 1’s
@ones = (5) x @ones; # Set all elements to 5
perl -e
is meant to execute Perl code from the command line:
$ perl --help Usage: perl [switches] [--] [programfile] [arguments] -e program one line of program (several -e's allowed, omit programfile)
CodePudding user response:
In Perl, you want to use the "x" operator.
Note the difference between
"4" x 4
and
("4") x 4
The former produces a repeated string:
"4444"
the latter a repeated list:
("4", "4", "4", "4")
CodePudding user response:
It's very similar in Perl
print "4" x 4;
CodePudding user response:
FWIW, it’s also print 4 x 4
in Perl.
In general, in Perl, operators are monomorphic, ie. you have different sets of operators for string semantics, for numeric semantics, for bitwise semantics, etc., where it makes sense, and the type of the operands largely doesn’t matter. When you apply a numeric operator to a string, the string is converted to a number first and you get the operation you asked for (eg. multiplication), and when you apply a string operator to a number, it’s turned into a string and you get the operation you asked for (eg. repetition). Perl pays attention to the operator first and the types of the operands only second – if indeed it pays them any mind at all.
This is the opposite of Python and most other languages, where you use one set of operators, and the types of the operands determine which semantics you’ll actually get – ie. operators are polymorphic.
CodePudding user response:
If you want to print 10 character "A"s, you can also do this
perl -e 'print "A" x 10'; echo
Example with output
user@linux:~$ perl -e 'print "A" x 10'; echo
AAAAAAAAAA
user@linux:~$
CodePudding user response:
All answers, given so far, missed mentioning that the operator x
does not only work on string literals, but also on variables that are strings or expressions that evaluate to strings like
use feature 'say';
my $msg = "hello ";
say $msg x 2;
say chr(33) x 3;
like this
hello hello
!!!
and, even more important, x
does an automatic conversion of expressions into strings if they aren't already (thanks to ggorlen for pointing me into that direction!). So for example
say 4 x 2;
say [$msg] x 2;
will result in something like the following as output
44
ARRAY(0x30ca10)ARRAY(0x30ca10)
CodePudding user response:
Came this way looking for an answer. Didn't quite find what I was looking for so I thought I'd share my learning. I wanted to compose dynamic SQL CRUD statements with the appropriate number of placeholders.
$table = "ORDERS";
@fields = ("ORDER_ID", "SALESMAN_ID", "CUSTOMER_ID", "ORDER_DATE", "STATUS");
$sql = "INSERT INTO $table (" . join(',', @fields) . ') VALUES (' . '?,' x (@fields - 1) . '?)';
print $sql;
The output looks like this...
INSERT INTO ORDERS (ORDER_ID,SALESMAN_ID,CUSTOMER_ID,ORDER_DATE,STATUS) VALUES (?,?,?,?,?)