> root# ps -ef | grep [j]ava |  awk '{print $2,$9}'                                                             
> 45134 -Dapex=APEC
> 45135 -Dapex=JAAA
> 45136 -Dapex=APEC

I need to put the first APEC of first as First PID, third line of APEC and Second PID and last one as Third PID.

I've tried awk but no expected result.

> First_PID =ps -ef | grep [j]ava |  awk '{print $2,$9}'|awk '{if ($0 == "[^0-9]" || $1 == "APEC:") {print $0; exit;}}'

Expected result should look like this.

> First_PID=45134
> Second_PID=45136
> Third_PID=45135

CodePudding user response：

With your shown samples and attempts please try following awk code. Written and tested in GNU awk.

ps -ef | grep [j]ava | 
awk '
{
  val=$2 OFS $9
  match(val,/([0-9] ) -Dapex=APEC ([0-9] ) -Dapex=JAAA\s([0-9] )/,arr)
  print "First_PID="arr[1],"Second_PID=",arr[3],"Third_PID=",arr[2]
}
'

CodePudding user response：

How about this:

$ input=("1 APEC" "2 JAAA" "3 APEC")
$ printf '%s\n' "${input[@]}" | grep APEC | sed -n '2p'
3 APEC

Explanation:

• input=(...) - input data in an array, for testing
• printf '%s\n' "${input[@]}" - print input array, one element per line
• grep APEC - keep lines containing APEC only
• sed -n - run sed without automatic print
• sed -n '2p' - print only the second line