Hey, I'm looking for some help with this question:

/*
Define a function called 'makeGrid'.

'makeGrid' should take in a number 'n' and some primitive value.

'makeGrid' should create a grid (an array of arrays), with the dimensions of n.

Return the grid filled with the given value.
*/

And here are some tests:

actual = makeGrid(2, "x");
expected = [
["x", "x"],
["x", "x"],
];

actual = makeGrid(3, false);
expected = [
[false, false, false],
[false, false, false],
[false, false, false],
];

I realise this should be a simple solution but I'm kinda lost in the woods with it, tried lots of different solutions but feel like I'm going around in circles. As I understand it I need to initialise the result with an empty array, then fill it with value * n number of arrays.

function makeGrid(n, value) {
let result = []

result.push(value * n)
}

This comes back undefined, which I understand, but any further clarity would be much appreciated. Thanks for taking the time to be here!

CodePudding user response：

You could do this with 2 steps:

• create n rows
• each row is filled with n times of value

const makeGrid = (n, value) => {
  return Array.from({ length: n }, _ => Array(n).fill(value))
}

console.log(makeGrid(2, "x"))

console.log(makeGrid(3, false))

Without Array.from

const makeGrid = (n, value) => {
  const rows = []

  for (let i = 0; i < n; i  ) {
    rows.push(Array(n).fill(value))
  }

  return rows
}

console.log(makeGrid(2, "x"))

console.log(makeGrid(3, false))

References

Array.from

Array.prototype.fill