My Python Recursive Function is returning None-CodePudding

I made a function that is being called recursively, and the condition for it to keep being called is a user input.

The recursion is working but the final value of the variable is being returned as None. I am a beginner at Python and i am trying to learn Functions and Recursion before going to Classes, OOP, Wrappers, etc.

Here is my code:

Main Py:

import funcoes_moeda

def switch(valor):
    case = int(input('Escolha uma opcao... (0 para encerrar) : '))
    if case == 1:
        valor = funcoes_moeda.aumentar(valor)
        print('Valor aumentado: {}'.format(valor))
        switch(valor)

    elif case == 2:
        pass
    elif case == 3:
        pass
    elif case == 4:
        pass
    else:
        return valor

valor = float(input('Insira o valor: '))
print("Escolha a funcao a ser aplicada no valor inserido: \n" \
    "1 - Aumentar Valor \n" \
    "2 - Diminuir Valor \n" \
    "3 - Dobrar Valor \n" \
    "4 - Dividir Valor \n" \
    "0 - Encerrar o Prorama"
    )

valor = switch(valor)

print('Funcao foi aplicada. O valor final ficou: {}'.format(valor))

Imported Functions:

def aumentar(valor):
    quantia_aumentada = float(input('Insira a quantidade que voce deseja acrescentar: '))
    valor  = quantia_aumentada
    return valor

def diminuir():
    pass

def dobro():
    pass

def metade():
    pass

When i tried executing this, what i got was:

Insira o valor: 100.00

Escolha a funcao a ser aplicada no valor inserido:

1 - Aumentar Valor

2 - Diminuir Valor

3 - Dobrar Valor

4 - Dividir Valor

0 - Encerrar o Prorama

Escolha uma opcao... (0 para encerrar) : 1

Insira a quantidade que voce deseja acrescentar: 100.00

Valor aumentado: 200.0

Escolha uma opcao... (0 para encerrar) : 1

Insira a quantidade que voce deseja acrescentar: 100.00

Valor aumentado: 300.0

Escolha uma opcao... (0 para encerrar) : 0

Funcao foi aplicada. O valor final ficou: None

For a test case, you can use:

Chose 100.00, option 1 (2 times is enough), increment 100.00 each call. Expected output: Current value = 300.00 (Because 100 100 100)

But i got None at the last print...

Please. What am i doing wrong??? :( Thank you for all the help.

PS: I tried going through the following answers, but i was not able to solve this problem because the explanation was for the problems in the question, and i found it was a litle different than mine..

1 > Recursive function returning none - Dint understand.

2 > python recursive function returning none instead of string - This is treating a CSV file.

CodePudding user response：

The problem is that when the case variable is equal to 0, the return valor statement is being executed within the switch() function, but this function is being called recursively so the value of valor is not being returned to the caller.

To fix this, you can add another return statement at the end of the switch() function that returns the value of valor when case is 0. This will ensure that the value of valor is returned to the caller, even when the switch() function is being called recursively.

def switch(valor):
    case = int(input('Escolha uma opcao... (0 para encerrar) : '))
    if case == 1:
        valor = funcoes_moeda.aumentar(valor)
        print('Valor aumentado: {}'.format(valor))
        switch(valor)

    elif case == 2:
        pass
    elif case == 3:
        pass
    elif case == 4:
        pass
    else:
        return valor

    # Return the value of valor when case is 0
    return valor

CodePudding user response：

When returning a value the recursion is braking and the value returns to the previous call of the function. If you want to return the value to the first call, you can return the value every time you call switch:

import funcoes_moeda

def switch(valor):
    case = int(input('Escolha uma opcao... (0 para encerrar) : '))
    if case == 1:
        valor = funcoes_moeda.aumentar(valor)
        print('Valor aumentado: {}'.format(valor))
        return switch(valor)

    elif case == 2:
        pass
    elif case == 3:
        pass
    elif case == 4:
        pass
    else:
        return valor

valor = float(input('Insira o valor: '))
print("Escolha a funcao a ser aplicada no valor inserido: \n" \
    "1 - Aumentar Valor \n" \
    "2 - Diminuir Valor \n" \
    "3 - Dobrar Valor \n" \
    "4 - Dividir Valor \n" \
    "0 - Encerrar o Prorama"
    )

valor = switch(valor)

print('Funcao foi aplicada. O valor final ficou: {}'.format(valor))

CodePudding user response：

Two issues:

The return at the end of the function 'switch' should be at the end of the function and not part of the 'else' case. Because if you select '1' you will change the value of 'valor', but after changing the value you exit the function withou returning a value.
The returned value of the recursive call to 'switch' in the code section of 'if case == 1:' is not saved and therefore lost.

If you only correct the first point above you will get changed values only from the top call to 'switch', but all changes from the recursive calls will get lost.

The solution proposed by thebjorn solves both above listed issues. But treating the issues one by one, might be easier to understand.