Let's say I have a list with multiple arrays:
L = [
array([-10, -8, -3, 2, 1]),
array([-9, -4, -1, 3, 5]),
array([-11, -5, -4, 0, 10])
]
How can I find the index of the lowest value the most efficiently?
For my example, the minimum value is -11 and the index is (2, 0), so the output should be (0, 2).
CodePudding user response:
What about the following?
import numpy as np
L = [
np.array([-10, -8, -3, 2, 1]),
np.array([-9, -4, -1, 3, 5]),
np.array([-11, -5, -4, 0, 10])
]
L_2d = np.array(L)
min_index = np.unravel_index(L_2d.argmin(), L_2d.shape)
(min_index[0], min_index[1])