I am writing the following shell script for generating multiple directories by providing arguments. This is my shell script "createDirectories1.sh"

#!/bin/bash

echo "$1"
echo "$2"
echo "$3"

mkdir $1{$2..$3}
#command mkdir $1{$2..$3}

And I am running the above script using following command

bash createDirectories1.sh week 1 5

And my expected output is Expected output

output which I am getting

This is how my terminal looks when giving commands to execute the script

I am not sure when I am running this command mkdir week{1..5} it works fine but when i run the same using shell script its not working

please help and let me know what modification is needed in my shell script ??

CodePudding user response：

You must use eval command. The eval command first evaluates the argument and then runs the command stored in the argument.

#!/bin/bash

echo "$1"
echo "$2"
echo "$3"

eval mkdir $1{$2..$3}

CodePudding user response：

this is what you need.

mkdir week_{1..5}

Let you know this answer : https://askubuntu.com/questions/731721/is-there-a-way-to-create-multiple-directories-at-once-with-mkdir

CodePudding user response：

bash ranges work with literals, not variables, so you need some way to eval {$2..$3}; the problem with evaling a string is that you have to ensure that it won't bite you:

#!/bin/bash

declare -a dirs="( $(printf '%q{%q..%q}' "$1" "$2" "$3") )"

mkdir "${dirs[@]}"

CodePudding user response：

Use for loop:

for ((i=$2; i<=$3; i  )); { mkdir "$1$i"; }