I tried reading the space-separated inputs 5 3 for my code using Scanner class which works fine using nextInt() method. When I switched to BufferReader class for faster I/O, using readLine() does not accept the space-separated inputs as separate integers.

import java.util.*;
import java.lang.*;
import java.io.*;


public class Main
{
    public static void main (String[] args) throws java.lang.Exception
    {
    
    try{
        InputStreamReader r=new InputStreamReader(System.in);    
    BufferedReader br=new BufferedReader(r); 
    int t= Integer.valueOf(br.readLine());
    
    while(t-->0){
        
    int mel=Integer.valueOf(br.readLine());
    
    int ban=Integer.valueOf(br.readLine());
    
    System.out.println(cho(mel,ban));
    
        
    }
    }catch(Exception e){
        return;
    }
    
    }
    
    public static int cho(int m,int b)
    
    {
        if(m==0 || b==0 || (m==b))
        {
            return (m b);
        }
        else
        {
           return m>b? cho((m-=b),b): cho(m,(b-=m));
            
           
            
        }
    }
}

**Inputs** 2 5 3 10 10 **Expected Outputs** 2 20

`My Outputs 2 5 3

...Program finished with exit code 0 Press ENTER to exit console. `

CodePudding user response：

Integer.valueOf(br.readLine()); reads the whole line and parses it to integer value so it expects only single integer value in the string. If you want to parse multiple integers from a line separated by space you first need to split it (or use do a regex search). For example br.readLine().split(" "); and then iterate over the array of strings and parse them as integers