python dictionaries within a list-CodePudding

I have the below dictionaries within a list:

price_list = [
     {'id': 1, 'name': 'apple', 'price': '100', 'year': '2000', 'currency': 'eur'},
     {'id': 2, 'name': 'apple', 'price': '150', 'year': '2022', 'currency': 'eur'},
     {'id': 3, 'name': 'apple', 'price': '1220', 'year': '160', 'currency': 'eur'},
     {'id': 4, 'name': 'apple', 'price': '150', 'year': '2080', 'currency': 'eur'}
]

The below code calculates the average price of the list:

for d in price_list:
    for _,item in d.items():
        total  = int(d['price'])
        count  = 1
        print(total,count)
        print('average=', total / count)

I want to be able to ignore anything within 10 years of the mid. So if i had an input of year = 2020, when querying against my list i will only want search back to 2010 and anything forward to 2030. Is this possible to implement?

CodePudding user response：

Look up the year and test it for the year range, then if it is an 'apple' then add the price so you calculate the average.

l = [{'id': 1, 'name': 'apple', 'price': '100', 'year': '2000', 'currency': 'eur'},    {'id': 2, 'name': 'apple', 'price': '150', 'year': '2022', 'currency': 'eur'},    {'id': 3, 'name': 'apple', 'price': '1220', 'year': '160', 'currency': 'eur'},    {'id': 4, 'name': 'apple', 'price': '150', 'year': '2080', 'currency': 'eur'}]

mid_year = 2020

total = 0
count = 0
for d in l:
    if int(d['year']) >= mid_year-10 and int(d['year']) <= mid_year 10:
        if d['name'] == 'apple':
            total  = int(d['price'])
            count  = 1

print('average=', total / count)

Runnable code: https://trinket.io/python3/1ab1232e44

CodePudding user response：

You can use a short for to make it one line

price = [int(d['price']) for d in price_list if int(d['year'])>year-10 and int(d['year'])<year 10]
print('average=', sum(price)/len(price)